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7/23/2009

SQL DATEDIFF Function

SQL DATEDIFF Function

Returns the number of date and time boundaries crossed between two dates

SQL DATEDIFF Syntax
DATEDIFF ( DatePart , StartDate , EndDate )

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate ='2007-06-05'
SET @EndDate ='2007-08-05'

SELECT DATEDIFF(Year, @StartDate, @EndDate) AS NewDate

Return Value = 0 Year


SELECT DATEDIFF(quarter, @StartDate, @EndDate) AS NewDate
Return Value = 1 quarter


SELECT DATEDIFF(Month, @StartDate, @EndDate) AS NewDate
Return Value = 2 Month


SELECT DATEDIFF(dayofyear,@StartDate, @EndDate) AS NewDate
Return Value = 61 day


SELECT DATEDIFF(Day, @StartDate, @EndDate) AS NewDate
Return Value = 61 Day


SELECT DATEDIFF(Week, @StartDate, @EndDate) AS NewDate
Return Value = 9 Week


SELECT DATEDIFF(Hour, @StartDate, @EndDate) AS NewDate
Return Value = 1464 Hour


SELECT DATEDIFF(minute, @StartDate, @EndDate) AS NewDate
Return Value = 87840 minute


SELECT DATEDIFF(second, @StartDate, @EndDate) AS NewDate
Return Value = 5270400 second


DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate ='2007-06-05'
SET @EndDate ='2007-06-06'

SELECT DATEDIFF(millisecond, @StartDate, @EndDate) AS NewDate

Return Value = 86400000 millisecon
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